z^2-4*z+(7-4*i)=0

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Solution for z^2-4*z+(7-4*i)=0 equation:


Simplifying
z2 + -4z + (7 + -4i) = 0

Remove parenthesis around (7 + -4i)
z2 + -4z + 7 + -4i = 0

Reorder the terms:
7 + -4i + -4z + z2 = 0

Solving
7 + -4i + -4z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -4i + -4z + -7 + z2 = 0 + -7

Reorder the terms:
7 + -7 + -4i + -4z + z2 = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -4i + -4z + z2 = 0 + -7
-4i + -4z + z2 = 0 + -7

Combine like terms: 0 + -7 = -7
-4i + -4z + z2 = -7

Add '4z' to each side of the equation.
-4i + -4z + 4z + z2 = -7 + 4z

Combine like terms: -4z + 4z = 0
-4i + 0 + z2 = -7 + 4z
-4i + z2 = -7 + 4z

Add '-1z2' to each side of the equation.
-4i + z2 + -1z2 = -7 + 4z + -1z2

Combine like terms: z2 + -1z2 = 0
-4i + 0 = -7 + 4z + -1z2
-4i = -7 + 4z + -1z2

Divide each side by '-4'.
i = 1.75 + -1z + 0.25z2

Simplifying
i = 1.75 + -1z + 0.25z2

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